Organometallic Compound ( QUIZ-1) 1 / 5 What are oxidation states of metal ion in following complexes?I. PdCl2 II. Pd(PPh3)4 III. Pd(OAc)2 IV. ArPdBr where Ar is aryl 2, 4, 2, 2 2, 0, 2, 1 2, 0, 2, 2 0, 0, 0, 2 n → oxidation states of metal ionPdCl2: n – 2 = 0 ⇒ n = 2Pd(PPh3)4 : Since PPh3 is neutral, Pd is in 0 Oxidation state.Pd(OAc)2: n – 2 = 0 ⇒ n = 2ArPdBr: n + [(–1) (–1)] ⇒ n = 2. 2 / 5 Which of the following complexes show easy oxidation? (η5-C5H5)2Fe (η5-C5H5)2Ru (η5-C5H5)2Co (η5-C5H5)2Co+ (a) (η5-C5H5)2Fe: VEC = 8 + 5 + 5 = 18(b) (η5-C5H5)2Ru: VEC = 8 + 5 + 5 = 18(c) (η5-C5H5)2Co: Since it is one e– extra of stable no., oxidation i.e. loss of e– can take place easily, VEC = 9 + 5 + 5 = 19(d) (η5-C5H5)2Co+: VEC = 9 + 5 + 5 – 1 = 18. 3 / 5 How many M — M bonds are present in [Cp Mo(CO3)]2? 1 2 0 4 No. of M-M bonds = (18×2-[(6+5+2×3)×2])/2=0. 4 / 5 Which of the following is the incorrect statement about Zeise’s salt? Zeise’s salt is diamagnetic Oxidation state of Pt in Zeis’s salt is +2 All the Pt-Cl bond length in Zeise’s salt are equal C-C bond length of ethylene moiety in Zeise’s salt longer than that of free ethylene molecule C2F4 is a better π acceptor than C2H4. So, metal-carbon bond order is more → Bond length is less in [PtCl3(C2F4)]– than in [PtCl3(C2H4)]–. 5 / 5 For metal olefin complexes (i) [PtCl3(C2F4)]– and (ii) [PtCl3(C2H4)]–, which of the following is the correct statement? carbon-carbon bond length is same both in (i) and (ii) carbon-carbon bond length in (i) is smaller carbon-carbon bond length in (ii) is smaller a metallacycle is formed in each complex Since Metal-C bond order in (i) is smaller than (ii) C–C bond order in (i) is larger than in (ii) & carbon-carbon bond length in (i) is smaller. Your score isThe average score is 70% 0% Restart quiz